Пример #1
0
void cross()
{
	int i , j , k ;
	int mask1 , mask2;
	int a[SUM];
	for(i = 0 ; i < SUM ; i++)  a[i] = 0;
	k = 0;
	for(i = 0 ; i < SUM ; i++)
	{
		if( a[i] == 0)
		{
			for( ; ; )//随机找到一组未进行过交叉的染色体与a[i]交叉
			{
   				j = randbit(i + 1 , SUM - 1);
				if( a[j] == 0)	break;
			}
			if(randsign(crossp) == 1)		//按照crossp的概率对选择的染色体进行交叉操作 
			{
				mask1 = createmask(randbit(0 , 14));		//由ranbit选择交叉位 
				mask2 = ~mask1;				//形成一个类似 111000 000111之类的二进制码编码 
				gen_new[k].info = (gen_group[i].info) & mask1 + (gen_group[j].info) & mask2;
				gen_new[k+1].info=(gen_group[i].info) & mask2 + (gen_group[j].info) & mask1;
				k = k + 2;
			}
			else 		//不进行交叉 
			{
				gen_new[k].info=gen_group[i].info;
				gen_new[k+1].info=gen_group[j].info;
				k=k+2;
			}
			a[i] = a[j] = 1;
		}
	}
}
Пример #2
0
// 1>随机选择将要进行交叉的染色体对,保证种群中的每个染色体都有唯一一次交叉的机会
// 2>按crossp的概率对选择的染色体对进行交叉操作
// 3>未进行交叉的染色体直接复制作为子染色体
void cross() { // 将父种群按概率crossp做交叉操作
  int i, j, k;
  int mask1, mask2;
  int a[SUM];
  for (i = 0; i < SUM; i++) a[i] = 0;
  k = 0;
  for (i = 0; i < SUM; i++) {
    if (a[i] == 0) {
      for ( ; ; ) {   // 随机找到一组未进行过交叉的染色体与a[i]交叉
        j = randbit(i + 1, SUM - 1);
        if (a[j] == 0) break;
      }
      if (randsign(crossp) == 1) {
        mask1 = createmask(randbit(0, 14));
        mask2 = -mask1;
        gen_new[k].info = (gen_group[i].info) & mask1 + (gen_group[j].info) & mask2;
        gen_new[k + 1].info = (gen_group[i].info) & mask2 + (gen_group[j].info) & mask1;
        k = k + 2;
      } else {
        gen_new[k].info = gen_group[i].info;
        gen_new[k + 1].info = gen_group[j].info;
        k = k + 2;
      }
      a[i] = a[j] = 1;
    }
  }
}
Пример #3
0
void mutation() {
  int i, j, m;
  int gentinfo;
  float x;
  float cmp;
  float gentsuitability;
  cmp = 1 - pow (1 - mp, 11); // 基因变异概率为mp时染色体中有基因发生变异的概率

  for (i = 0; i < SUM; i++) {
    if (randsign(cmp) == 1) {
      j = randbit(0, 14);
      m = 1 << j;
      gen_group[i].info = gen_group[i].info ^ m;
      x = convertionB2D(gen_group[i].info);
      x = x * (x * (x * (x * (x * (x - 10) - 26) + 344) + 193) - 1846) - 1680;
      gen_group[i].suitability = x;
    }
  }
  for (i = 0; i < SUM - 1; i++) {
    for (j = i + 1; j < SUM; j++) {
      if (gen_group[i].suitability > gen_group[j].suitability) {
        gentinfo = gen_group[i].info;
        gen_group[i].info = gen_group[j].info;
        gen_group[j].info = gentinfo;
        gentsuitability = gen_group[i].suitability;
        gen_group[i].suitability = gen_group[j].suitability;
        gen_group[j].suitability = gentsuitability;
      }
    }
  }
}
Пример #4
0
void mutation()
{
	int i , j , m;
	float x;
	float gmp;
	int gentinfo;
	float gentsuitability;
	gmp = 1 - pow(1 - mp , 11);//在基因变异概率为mp时整条染色体的变异概率
	for(i = 0 ; i < SUM ; i++)
	{
		if(randsign(gmp) == 1)
		{
			j = randbit(0 , 14);
			m = 1 << j;
			gen_group[i].info = gen_group[i].info^m;
			x = convertionB2D(gen_group[i].info);
			gen_group[i].suitability = x*(x*(x*(x*(x*(x-10)-26)+344)+193)-1846)-1680;
		}
	}
	for(i = 0 ; i < SUM - 1 ; i++)
	{
		for(j = i + 1 ; j < SUM ; j++)
		{
			if(gen_group[i].suitability > gen_group[j].suitability)
			{
				gentinfo = gen_group[i].info;
				gen_group[i].info = gen_group[j].info;
				gen_group[j].info = gentinfo;
				
				gentsuitability = gen_group[i].suitability;
				gen_group[i].suitability = gen_group[j].suitability;
				gen_group[j].suitability = gentsuitability;
			}
		}
	}
	/*
	*为了提高执行速度,在进行变异操作的时候并没有直接确定需要进行变异的位
	*而是先以cmp概率确定将要发生变异的染色体,再从染色体中随进选择一个基因进行变异
	*由于进行选择和变异后父代种群的次序已被打乱,因此,在变异前后对种群进行一次排序 
	*/ 
}
Пример #5
0
// calculate a new stock value (based on previous value)
static double 
revalue (const double last) 
{ 
  return last + randsign() * randf(); 
}