Пример #1
0
static inline void
bitmap_element_free (bitmap head, bitmap_element *elt)
{
  bitmap_element *next = elt->next;
  bitmap_element *prev = elt->prev;

  if (prev)
    prev->next = next;

  if (next)
    next->prev = prev;

  if (head->first == elt)
    head->first = next;

  /* Since the first thing we try is to insert before current,
     make current the next entry in preference to the previous.  */
  if (head->current == elt)
    {
      head->current = next != 0 ? next : prev;
      if (head->current)
	head->indx = head->current->indx;
      else
	head->indx = 0;
    }

  if (GATHER_STATISTICS)
    register_overhead (head, -((int)sizeof (bitmap_element)));

  bitmap_elem_to_freelist (head, elt);
}
Пример #2
0
static void *
vec_heap_o_reserve_1 (void *vec, int reserve, size_t vec_offset,
		      size_t elt_size, bool exact MEM_STAT_DECL)
{
  struct vec_prefix *pfx = (struct vec_prefix *) vec;
  unsigned alloc = calculate_allocation (pfx, reserve, exact);

  if (!alloc)
    {
      if (pfx)
        vec_heap_free (pfx);
      return NULL;
    }

#ifdef GATHER_STATISTICS
  if (vec)
    free_overhead (pfx);
#endif
  
  vec = xrealloc (vec, vec_offset + alloc * elt_size);
  ((struct vec_prefix *)vec)->alloc = alloc;
  if (!pfx)
    ((struct vec_prefix *)vec)->num = 0;
#ifdef GATHER_STATISTICS
  if (vec)
    register_overhead ((struct vec_prefix *)vec,
    		       vec_offset + alloc * elt_size PASS_MEM_STAT);
#endif
  
  return vec;
}
Пример #3
0
static inline bitmap_element *
bitmap_element_allocate (bitmap head)
{
  bitmap_element *element;
  bitmap_obstack *bit_obstack = head->obstack;

  if (bit_obstack)
    {
      element = bit_obstack->elements;

      if (element)
	/* Use up the inner list first before looking at the next
	   element of the outer list.  */
	if (element->next)
	  {
	    bit_obstack->elements = element->next;
	    bit_obstack->elements->prev = element->prev;
	  }
	else
	  /*  Inner list was just a singleton.  */
	  bit_obstack->elements = element->prev;
      else
	element = XOBNEW (&bit_obstack->obstack, bitmap_element);
    }
  else
    {
      element = bitmap_ggc_free;
      if (element)
	/* Use up the inner list first before looking at the next
	   element of the outer list.  */
	if (element->next)
	  {
	    bitmap_ggc_free = element->next;
	    bitmap_ggc_free->prev = element->prev;
	  }
	else
	  /*  Inner list was just a singleton.  */
	  bitmap_ggc_free = element->prev;
      else
	element = ggc_alloc<bitmap_element> ();
    }

  if (GATHER_STATISTICS)
    register_overhead (head, sizeof (bitmap_element));

  memset (element->bits, 0, sizeof (element->bits));

  return element;
}
Пример #4
0
void
bitmap_elt_clear_from (bitmap head, bitmap_element *elt)
{
  bitmap_element *prev;
  bitmap_obstack *bit_obstack = head->obstack;

  if (!elt) return;

  if (GATHER_STATISTICS)
    {
      int n = 0;
      for (prev = elt; prev; prev = prev->next)
	n++;
      register_overhead (head, -sizeof (bitmap_element) * n);
    }

  prev = elt->prev;
  if (prev)
    {
      prev->next = NULL;
      if (head->current->indx > prev->indx)
	{
	  head->current = prev;
	  head->indx = prev->indx;
	}
    }
  else
    {
      head->first = NULL;
      head->current = NULL;
      head->indx = 0;
    }

  /* Put the entire list onto the free list in one operation. */
  if (bit_obstack)
    {
      elt->prev = bit_obstack->elements;
      bit_obstack->elements = elt;
    }
  else
    {
      elt->prev = bitmap_ggc_free;
      bitmap_ggc_free = elt;
    }
}