void signal(ValueType const& val, boost::uint64_t count)
{ // {{{
// push back the new value onto the queue
HPX_STD_UNIQUE_PTR<queue_value_entry> node
(new queue_value_entry(val, count));
mutex_type::scoped_lock l(mtx_);
value_queue_.push_back(*node);
node.release();
resume(l);
} // }}}
///////////////////////////////////////////////////////////////////////
// create a new thread and schedule it if the initial state is equal to
// pending
thread_id_type create_thread(thread_init_data& data,
thread_state_enum initial_state, bool run_now,
std::size_t num_thread, error_code& ec)
{
if (run_now) {
mutex_type::scoped_lock lk(mtx_);
HPX_STD_UNIQUE_PTR<threads::thread_data> thrd (
new (memory_pool_) threads::thread_data(
data, memory_pool_, initial_state));
// add a new entry in the map for this thread
thread_id_type id = thrd->get_thread_id();
std::pair<thread_map_type::iterator, bool> p =
thread_map_.insert(id, thrd.get());
if (HPX_UNLIKELY(!p.second)) {
HPX_THROWS_IF(ec, hpx::out_of_memory,
"threadmanager::register_thread",
"Couldn't add new thread to the map of threads");
return invalid_thread_id;
}
// push the new thread in the pending queue thread
if (initial_state == pending)
schedule_thread(thrd.get(), num_thread);
// this thread has to be in the map now
BOOST_ASSERT(thread_map_.find(id) != thread_map_.end());
BOOST_ASSERT(thrd->is_created_from(&memory_pool_));
do_some_work(); // try to execute the new work item
thrd.release(); // release ownership to the map
if (&ec != &throws)
ec = make_success_code();
// return the thread_id of the newly created thread
return id;
}
// do not execute the work, but register a task description for
// later thread creation
#if HPX_THREAD_MAINTAIN_QUEUE_WAITTIME
new_tasks_.enqueue(new task_description(
boost::move(data), initial_state,
util::high_resolution_clock::now()
));
#else
new_tasks_.enqueue(new task_description(
boost::move(data), initial_state));
#endif
++new_tasks_count_;
if (&ec != &throws)
ec = make_success_code();
return invalid_thread_id; // thread has not been created yet
}