示例#1
0
int c_invert( double incoef[6],	/* Transformation coefficients--input */
	      double coef[6]	/* Inverted transformation coefficients */
     )
{
    double det;			/* Determinate */
    double maximum;		/* Maximum input coefficient value */
    double max1, max2;		/* Temporary variables for max calculation */

/* Find the determinate 
 ---------------------*/
    det = ( incoef[3] * incoef[1] ) - ( incoef[4] * incoef[0] );

/* Find the maximum coefficent value 
 ----------------------------------*/
    max1 = CMAX( fabs( incoef[0] ), fabs( incoef[1] ) );
    max2 = CMAX( fabs( incoef[3] ), fabs( incoef[4] ) );
    maximum = CMAX( max1, max2 );

/* Is the determinant of the coefficients too near zero?
 ----------------------------------------------------------------------*/
    if ( fabs( det ) < ( EPSLNX * maximum ) )
    {
	ErrorHandler( FALSE, "c_invert", ERROR_PROJECTION_MATH,
		      "Determinant too near zero" );
	return ( E_GEO_FAIL );
    }

/* Compute inverse coefficients 
 -----------------------------*/
    coef[0] = -( incoef[4] ) / det;
    coef[1] = incoef[1] / det;
    coef[2] = ( ( incoef[4] * incoef[2] ) - ( incoef[1] * incoef[5] ) ) / det;
    coef[3] = incoef[3] / det;
    coef[4] = -( incoef[0] ) / det;
    coef[5] = ( ( incoef[0] * incoef[5] ) - ( incoef[3] * incoef[2] ) ) / det;

    return ( E_GEO_SUCC );
}
示例#2
0
void BvcEncoder::decompose_block(const u_char* in, int8_t* out)
{
	int32_t scratch[CMAX(2*8*18/4, 64)];
	u_int8_t* l = (u_int8_t*)scratch;
	int8_t* h = (int8_t*)&l[8*18];
	int stride = width_;
	in -= 1;
	for (int w = 18; --w >= 0; ) {
		int8_t* cl = (int8_t*)(l++);
		int8_t* ch = h++;
		const u_char* p = in++;
		int in0 = p[-stride];
		int in1 = *p;
		p += stride;
		for (int th = 8; --th >= 0; ) {
			int in2 = *p;
			p += stride;
			int in3 = *p;
			p += stride;

			/* multiply by 3 */
			int m1 = in1 + (in1 << 1);
			int m2 = in2 + (in2 << 1);

			/* -1 3 3 -1 */
			int v = m1 + m2 - in0 - in3;
			v >>= 2;
			if (v & ~0xff)
				v = (v < 0) ? 0 : 255;
			*cl = v;
			cl += 18;

			/* 1 -3 3 -1 */
			v = in0 - m1 + m2 - in3;
			v >>= 2;
			if ((v + 127) & ~0xff)
				v = (v < -128) ? -128 : 127;
			*ch = v;
			ch += 18;

			in0 = in2;
			in1 = in3;
		}
	}
	/* rows */
	const u_int8_t* p = (u_int8_t*)scratch;
	l = (u_int8_t*)out;
	h = out + 2*64;
	int th;
	for (th = 8; --th >= 0; ) {
		int in0 = *p++;
		int in1 = *p++;
		for (int w = 8; --w >= 0; ) {
			int in2 = *p++;
			int in3 = *p++;

			/* multiply by 3 */
			int m1 = in1 + (in1 << 1);
			int m2 = in2 + (in2 << 1);

			/* -1 3 3 -1 */
			int v = m1 + m2 - in0 - in3;
			v >>= 2;
			if (v & ~0xff)
				v = (v < 0) ? 0 : 255;
			*l++ = v;
			/* 1 -3 3 -1 */
			v = in0 - m1 + m2 - in3;
			v >>= 2;
			if ((v + 127) & ~0xff)
				v = (v < -128) ? -128 : 127;
			*h++ = v;

			in0 = in2;
			in1 = in3;
		}
	}
	for (th = 8; --th >= 0; ) {
		int in0 = *(int8_t*)(p++);
		int in1 = *(int8_t*)(p++);
		for (int w = 8; --w >= 0; ) {
			int in2 = *(int8_t*)(p++);
			int in3 = *(int8_t*)(p++);

			/* multiply by 3 */
			int m1 = in1 + (in1 << 1);
			int m2 = in2 + (in2 << 1);

			/* -1 3 3 -1 */
			int v = m1 + m2 - in0 - in3;
			*l++ = v >> 2;
#ifdef HAVE_HH
			/* 1 -3 3 -1 */
			v = in0 - m1 + m2 - in3;
			*h++ = v >> 2;
#endif

			in0 = in2;
			in1 = in3;
		}
	}

	/* now apply fully separable Haar tranform remaining 8x8 subimage */

	/* columns */
	l = (u_int8_t*)out;
	int32_t* o = scratch;
	int k;
	for (k = 8; --k >= 0; ) {
		/* use fixed point arithmetic with 2 bits of fraction */
		int t0 = l[0*8];
		int t1 = l[1*8];
		int t2 = t0 + t1;
		o[4*8] = (t1 - t0) << 2;

		t0 = l[2*8];
		t1 = l[3*8];
		int t3 = t0 + t1;
		o[5*8] = (t1 - t0) << 2;

		t0 = l[4*8];
		t1 = l[5*8];
		int t4 = t0 + t1;
		o[6*8] = (t1 - t0) << 2;

		t0 = l[6*8];
		t1 = l[7*8];
		int t5 = t0 + t1;
		o[7*8] = (t1 - t0) << 2;

		t0 = t2 + t3;
		t1 = t4 + t5;
		o[0*8]  = t0 + t1;
		o[1*8]  = t1 - t0;
		o[2*8] = (t3 - t2) << 1;
		o[3*8] = (t5 - t4) << 1;

		++o;
		++l;
	}
	/* rows */
	o = scratch;
	l = (u_int8_t*)out;
	for (k = 8; --k >= 0; ) {
		int t0 = o[0];
		int t1 = o[1];
		int t2 = t0 + t1;
		l[4] = (t1 - t0 + 7) >> 4;

		t0 = o[2];
		t1 = o[3];
		int t3 = t0 + t1;
		l[5] = (t1 - t0 + 7) >> 4;

		t0 = o[4];
		t1 = o[5];
		int t4 = t0 + t1;
		l[6] = (t1 - t0 + 7) >> 4;

		t0 = o[6];
		t1 = o[7];
		int t5 = t0 + t1;
		l[7] = (t1 - t0 + 7) >> 4;

		t0 = t2 + t3;
		t1 = t4 + t5;
		l[0] = (t0 + t1 + 31) >> 6;
		l[1] = (t1 - t0 + 31) >> 6;
		l[2] = (t3 - t2 + 15) >> 5;
		l[3] = (t5 - t4 + 15) >> 5;

		l += 8;
		o += 8;
	}
}