示例#1
0
/**
 * After a long period with no updates (map setup), calling this will reset
 * the tictimer so that no time seems to have passed.
 */
void Net_ResetTimer(void)
{
    int i;

    firstNetUpdate = true;

    for(i = 0; i < DDMAXPLAYERS; ++i)
    {
        if(/*!clients[i].connected ||*/ !clients[i].smoother) continue;
        Smoother_Clear(clients[i].smoother);
    }
}
示例#2
0
void Smoother_AddPos(Smoother *sm, float time, coord_t x, coord_t y, coord_t z, dd_bool onFloor)
{
    pos_t *last;
    DENG_ASSERT(sm);

    // Is it the same point?
    last = &sm->points[SM_NUM_POINTS - 1];
    if(last->time == time)
    {
        if(last->xyz[VX] == x && last->xyz[VY] == y && last->xyz[VZ] == z)
        {
            // Ignore it.
            return;
        }

        // Readjusting a previously set value?
        goto replaceLastPoint;
    }

    if(time <= sm->now.time)
    {
        // The new point would be in the past, this is no good.
#ifdef _DEBUG
        LOG_DEBUG("Smoother_AddPos: DISCARDING new pos, time=%f, now=%f.") << time << sm->now.time;
#endif
        Smoother_Clear(sm);
        return;
    }

    // If we are about to discard an unused future point, we will force
    // the current interpolation into the future.
    if(Smoother_IsValid(sm) && sm->points[0].time > sm->now.time)
    {
        coord_t mid[3];
        float remaining;

        // Move the past forward in time so that the interpolation remains continuous.
        remaining = sm->now.time - sm->at;

        Smoother_Evaluate(sm, mid);
        sm->at = sm->past.time = sm->points[0].time - remaining;
        sm->past.xyz[VX] = mid[VX];
        sm->past.xyz[VY] = mid[VY];
        sm->past.xyz[VZ] = mid[VZ];

        // Replace the now with the point about to be discarded.
        memcpy(&sm->now, &sm->points[0], sizeof(pos_t));
    }

    // Rotate the old points.
    memmove(&sm->points[0], &sm->points[1], sizeof(pos_t) * (SM_NUM_POINTS - 1));

replaceLastPoint:
    last = &sm->points[SM_NUM_POINTS - 1];
    last->time = time;
    last->xyz[VX] = x;
    last->xyz[VY] = y;
    last->xyz[VZ] = z;
    last->onFloor = onFloor;

    // Is this the first one?
    if(sm->now.time == 0)
    {
        sm->at = time;
        memcpy(&sm->past, last, sizeof(pos_t));
        memcpy(&sm->now, last, sizeof(pos_t));
    }
}