C++ (Cpp) flushContiguous示例

示例#1

文件： cache.c 项目： HumbleRepose/transmission

static int
flushRuns( tr_cache * cache, struct run_info * runs, int n )
{
    int i, j, err = 0;

    for( i = 0; !err && i < n; ++i )
    {
        err = flushContiguous( cache, runs[i].pos, runs[i].len );
        for( j = i + 1; j < n; ++j )
            if( runs[j].pos > runs[i].pos )
                runs[j].pos -= runs[i].len;
    }

    return err;
}

示例#2

文件： cache.c 项目： Mikayex/transmission

static int flushRuns(tr_cache* cache, struct run_info* runs, int n)
{
    int err = 0;

    for (int i = 0; err == 0 && i < n; i++)
    {
        err = flushContiguous(cache, runs[i].pos, runs[i].len);

        for (int j = i + 1; j < n; j++)
        {
            if (runs[j].pos > runs[i].pos)
            {
                runs[j].pos -= runs[i].len;
            }
        }
    }

    return err;
}