示例#1
0
文件: word.c 项目: TEJESH/word_setup
int funct3(int n)
{
	a = n%10;
	q = n%100;
	b = n/10;

	c = b%10;
	d = b/10;

	funct1(d);
	printf(" hundred & ");
	if(q>10 && q<20)
	{
		funct5(q);
	}
	else
	{
	funct4(c);
	printf("-");
	//printf("ty");
	funct1(a);
	}
	//printf("\n");
	
	return n;
}
示例#2
0
int main()
{
   int a = 10;
   int b = 25;
   funct1(a, b);
   funct1(20, 10);
   return 0;
}
示例#3
0
文件: q5b.c 项目: eokeeffe/C-code
void main()
{
	double x , y, z;

 z = funct1 ( x , y);

}
示例#4
0
文件: word.c 项目: TEJESH/word_setup
int funct2(int n)
{
	m = n%10;
	o = n/10;
		funct4(o);
		//printf("ty");
		funct1(m);
	//printf("\n");
	return n;
}
示例#5
0
文件: word.c 项目: TEJESH/word_setup
void main()
{	
	int n;
	printf("enter no: \a\n");
	scanf("%d",&n);

	if(n<10)
	{
		funct1(n);
	}
	else if(n>=10 && n<100)
	{	
		if(n%10==0)
		{
			w=n/10;
			funct4(w);
			
		}
	     	else if(n>10 && n<20)
		{
			funct5(n);
		}
		else
		{	
			funct2(n);
		}	
	}
	else if(n>=100 && n<1000)
	{
		funct3(n);
	}
	

	else
		printf("no. out of range");
	printf("\n");
	
}
示例#6
0
long int CDate::DayCount(int m, int d, int y) {
	return 1461 *  funct1(y,m) / 4 + 153 * funct2(m) / 5 + d;
}