bool isInterleave(string s1, string s2, string s3) {
     // Start typing your C/C++ solution below
     // DO NOT write int main() function   
     if( s1.size() + s2.size() != s3.size() )
         return false;
     
     // save space
     if( s2.size() > s1.size() ){
         string temp = s1;
         s1=s2;
         s2=temp;
     }
     
     vector<bool> isInter(s2.size()+1, false);   
     // initialize the first row
     for( int i = 0; i <= s2.size(); i++){
         if( s2.substr(0,i) != s3.substr(0,i) )
             break;
         isInter[i] = true;
     }
     
     // treat each inner loop's isInter as isInter[i][j], the isInter[i-1][j] is the same as the one
     // on the right side of the assign line inner most
     for( int i = 1; i <= s1.size(); i ++){
         isInter[0] = ( s1.substr(0,i) == s3.substr(0,i) );
         for( int j = 1; j <= s2.size(); j++){
             isInter[j]=(s2[j-1]==s3[i+j-1] && isInter[j-1] ) || ( s1[i-1]==s3[i+j-1] && isInter[j] );
         }
     }
     return isInter[s2.size()];
 }
示例#2
0
 bool isInter(string &s1, string &s2, string &s3, int pos1, int pos2)
 {
     int len1 = s1.size();
     int len2 = s2.size();
     int len3 = s3.size();
     int pos3 = pos1+pos2;
     
     if(pos3 == len3)
         return true;
     
     if(pos1< len1 && s1[pos1] ==s3[pos3])
     {
         if(isInter(s1, s2, s3, pos1+1, pos2))
             return true;
     }
     if(pos2< len2 && s2[pos2] ==s3[pos3])
     {
         if(isInter(s1, s2, s3, pos1, pos2+1))
             return true;
     }
     return false;
 }
 bool isInterleave(string s1, string s2, string s3) { 
     
     if( s1.size() + s2.size() != s3.size() ) return false;
     vector<vector<bool>> isInter( s1.size()+1, vector<bool>(s2.size()+1, false) );
     
     isInter[0][0] = true;
     
     int it = 1;
     while( it <= s1.size() && s1[it-1] == s3[it-1] ){
         isInter[it][0] = true;
         it ++;
     }
     
     it = 1;
     
     while( it <= s2.size() && s2[it-1] == s3[it-1] ){
         isInter[0][it] = true;
         it ++;
     }
     
     for( int s1_it = 1; s1_it <= s1.size(); s1_it ++ ){
         for( int s2_it = 1; s2_it <= s2.size(); s2_it ++ ){
             // check if isInter[s1_it][s2_it] is true?
             // two cases
             char temp_char = s3[s1_it + s2_it -1] ;
             
             // if s1[s1_it-1] == s3[s1_it + s2_it -1], isInter[s1_it][s2_it] will be true
             // if isInter[s1_it - 1][s2_it] is true
             if( temp_char == s1[s1_it-1] )
                 isInter[s1_it][s2_it] = isInter[s1_it-1][s2_it];
             if( temp_char == s2[s2_it-1] )
                 isInter[s1_it][s2_it] = isInter[s1_it][s2_it-1] || isInter[s1_it][s2_it];
         } 
     }
     
     return isInter[s1.size()][s2.size()];
 }
示例#4
0
 bool isInterleave(string s1, string s2, string s3) {
     if(s1.size()+s2.size() != s3.size())
         return false;
     return isInter(s1, s2, s3, 0, 0);
 }