示例#1
0
文件: tcp.c 项目: zsh-users/zsh
/* "allocate" a tcp_session */
static Tcp_session
zts_alloc(int ztflags)
{
    Tcp_session sess;

    sess = (Tcp_session)zshcalloc(sizeof(struct tcp_session));
    if (!sess) return NULL;
    sess->fd=-1;
    sess->flags=ztflags;

    zinsertlinknode(ztcp_sessions, lastnode(ztcp_sessions), (void *)sess);

    return sess;
}
示例#2
0
 ListNode *sortList(ListNode *head) {
   if(head==NULL)
     return NULL;
   SortRec(head,lastnode(head));//2,1
   return head;
 }
示例#3
0
LinkNode
stringsubst(LinkList list, LinkNode node, int ssub)
{
    int qt;
    char *str3 = (char *)getdata(node);
    char *str  = str3;

    while (!errflag && *str) {
	if ((qt = *str == Qstring) || *str == String)
	    if (str[1] == Inpar) {
		str++;
		goto comsub;
	    } else if (str[1] == Inbrack) {
		/* $[...] */
		char *str2 = str;
		str2++;
		if (skipparens(Inbrack, Outbrack, &str2)) {
		    zerr("closing bracket missing", NULL, 0);
		    return NULL;
		}
		str2[-1] = *str = '\0';
		str = arithsubst(str + 2, &str3, str2);
		setdata(node, (void *) str3);
		continue;
	    } else {
		node = paramsubst(list, node, &str, qt, ssub);
		if (errflag || !node)
		    return NULL;
		str3 = (char *)getdata(node);
		continue;
	    }
	else if ((qt = *str == Qtick) || *str == Tick)
	  comsub: {
	    LinkList pl;
	    char *s, *str2 = str;
	    char endchar;
	    int l1, l2;

	    if (*str == Inpar) {
		endchar = Outpar;
		str[-1] = '\0';
		if (skipparens(Inpar, Outpar, &str))
		    DPUTS(1, "Oops. parse error in command substitution");
		str--;
	    } else {
		endchar = *str;
		*str = '\0';

		while (*++str != endchar)
		    DPUTS(!*str, "Oops. parse error in command substitution");
	    }
	    *str++ = '\0';
	    if (endchar == Outpar && str2[1] == '(' && str[-2] == ')') {
		/* Math substitution of the form $((...)) */
		str = arithsubst(str2 + 1, &str3, str);
		setdata(node, (void *) str3);
		continue;
	    }

	    /* It is a command substitution, which will be parsed again   *
	     * by the lexer, so we untokenize it first, but we cannot use *
	     * untokenize() since in the case of `...` some Bnulls should *
	     * be left unchanged.  Note that the lexer doesn't tokenize   *
	     * the body of a command substitution so if there are some    *
	     * tokens here they are from a ${(e)~...} substitution.       */
	    for (str = str2; *++str; )
		if (itok(*str) && *str != Nularg &&
		    !(endchar != Outpar && *str == Bnull &&
		      (str[1] == '$' || str[1] == '\\' || str[1] == '`' ||
		       (qt && str[1] == '"'))))
		    *str = ztokens[*str - Pound];
	    str++;
	    if (!(pl = getoutput(str2 + 1, qt || ssub))) {
		zerr("parse error in command substitution", NULL, 0);
		return NULL;
	    }
	    if (endchar == Outpar)
		str2--;
	    if (!(s = (char *) ugetnode(pl))) {
		str = strcpy(str2, str);
		continue;
	    }
	    if (!qt && ssub && isset(GLOBSUBST))
		tokenize(s);
	    l1 = str2 - str3;
	    l2 = strlen(s);
	    if (nonempty(pl)) {
		LinkNode n = lastnode(pl);
		str2 = (char *) ncalloc(l1 + l2 + 1);
		strcpy(str2, str3);
		strcpy(str2 + l1, s);
		setdata(node, str2);
		insertlinklist(pl, node, list);
		s = (char *) getdata(node = n);
		l1 = 0;
		l2 = strlen(s);
	    }
	    str2 = (char *) ncalloc(l1 + l2 + strlen(str) + 1);
	    if (l1)
		strcpy(str2, str3);
	    strcpy(str2 + l1, s);
	    str = strcpy(str2 + l1 + l2, str);
	    str3 = str2;
	    setdata(node, str3);
	    continue;
	}
	str++;
    }
    return errflag ? NULL : node;
}