示例#1
0
文件: update.c 项目: yin-nadie/wodox
/*----------------------------------------------------------------------------
 * Check state for all dynamic circuits. These may activate and deactivate
 * moving blocks.
 *----------------------------------------------------------------------------*/
void
update_dynamic_circuit(struct dynamic_circuit *d)
{
    if (calculate(d->tree, 0)) {
        switch (d->obj->type) {
        case MOVING_0:
            if (object_try_move(d->obj, DIR_DN)) {
                MAP[idx_dn(d->obj->idx)] = MOVING_1;
                d->obj->type = MOVING_1;
                if (media.enable_audio)
                    Mix_PlayChannel(CHANNEL_OPEN, media.chunk_open, 0);
            }
            break;
        }
    } else {
        switch (d->obj->type) {
        case MOVING_1:
            if (levitate(d->obj)) {
                MAP[idx_up(d->obj->idx)] = MOVING_0;
                d->obj->type = MOVING_0;
                if (media.enable_audio)
                    Mix_PlayChannel(CHANNEL_OPEN, media.chunk_open, 0);
            }
            break;
        }
    }
}
示例#2
0
文件: update.c 项目: yin-nadie/wodox
/*----------------------------------------------------------------------------
 * Move an object up, pushing every other object on its way if possible.
 *----------------------------------------------------------------------------*/
int
levitate(struct object *o)
{
    struct object *tmp;

    if (idx_y(o->idx) == MAX)
        return 0;

    if ((tmp = OBJ[idx_up(o->idx)]) && tmp->dir == STILL) {
        if (levitate(tmp)) {
            object_move(o, DIR_UP);
            return DIR_UP;
        }

        return STILL;
    }

    return object_try_move(o, DIR_UP);
}
示例#3
0
文件: update.c 项目: yin-nadie/wodox
/*----------------------------------------------------------------------------
 * Heavy objects are subject to forces. Depending on the value of the space in
 * the forces map, they can go either up, down or nowhere, but if they ought to
 * go up and are unable to do so or the space has no force they might be
 * affected by a conveyor belt. For these checks we must iterate on the object
 * map because order matters: objects in higher layers have priority.
 *----------------------------------------------------------------------------*/
void
update_heavy_object(struct object *o)
{
    if (o->dir != STILL)
        return;

    switch (FRC[o->idx]) {
    case DIR_DN:
        if (idx_y(o->idx) > MIN && object_try_move(o, DIR_DN))
            return;
        break;
    case DIR_UP:
        if (levitate(o))
            return;
        break;
    }

    switch (MAP[idx_dn(o->idx)]) {
    case BELT_LF_1:
        if (idx_x(o->idx) > MIN)
            object_try_move(o, DIR_LF);
        break;
    case BELT_RT_1:
        if (idx_x(o->idx) < MAX)
            object_try_move(o, DIR_RT);
        break;
    case BELT_BK_1:
        if (idx_z(o->idx) > MIN)
            object_try_move(o, DIR_BK);
        break;
    case BELT_FT_1:
        if (idx_z(o->idx) < MAX)
            object_try_move(o, DIR_FT);
        break;
    }
}
示例#4
0
void s_levitate(void)
{
    levitate(0);
}
示例#5
0
void i_levitate(pob o)
{
    if (o->known < 1) o->known = 1;
    Objects[o->id].known = 1;
    levitate(o->blessing);
}