示例#1
0
static int
testmult(void)
{

	mp_mult(c5, c2, t0);
	testmcmp(t0, c10, "mmult0");
	mp_mult(c3, c14, t0);
	testmcmp(t0, c42, "mmult1");
}
示例#2
0
void
mp_invert(MINT *x1, MINT *x0, MINT *c)
{
	MINT u2, u3;
	MINT v2, v3;
	MINT zero;
	MINT q, r;
	MINT t;
	MINT x0_prime;
	static MINT *one = NULL;

	/*
	 * Minimize calls to allocators.  Don't use pointers for local
	 * variables, for the one "initialized" multiple precision
	 * variable, do it just once.
	 */
	if (one == NULL)
		one = mp_itom(1);

	zero.len = q.len = r.len = t.len = 0;

	x0_prime.len = u2.len = u3.len = 0;
	_mp_move(x0, &u3);
	_mp_move(x0, &x0_prime);

	v2.len = v3.len = 0;
	_mp_move(one, &v2);
	_mp_move(x1, &v3);

	while (mp_mcmp(&v3, &zero) != 0) {
		/* invariant: x0*u1 + x1*u2 = u3 */
		/* invariant: x0*v1 + x2*v2 = v3 */
		/* invariant: x(n+1) = x(n-1) % x(n) */
		mp_mdiv(&u3, &v3, &q, &r);
		_mp_move(&v3, &u3);
		_mp_move(&r, &v3);

		mp_mult(&q, &v2, &t);
		mp_msub(&u2, &t, &t);
		_mp_move(&v2, &u2);
		_mp_move(&t, &v2);
	}
	/* now x0*u1 + x1*u2 == 1, therefore,  (u2*x1) % x0  == 1 */
	_mp_move(&u2, c);
	if (mp_mcmp(c, &zero) < 0) {
		mp_madd(&x0_prime, c, c);
	}
	_mp_xfree(&zero);
	_mp_xfree(&v2);
	_mp_xfree(&v3);
	_mp_xfree(&u2);
	_mp_xfree(&u3);
	_mp_xfree(&q);
	_mp_xfree(&r);
	_mp_xfree(&t);
}
示例#3
0
/* Converts a possibly-signed digit string into a large binary number.
   Returns assumed radix, derived from suffix 'h','o',b','.' */
int str2reg(unitptr reg, string digitstr)
{
    unit temp[MAX_UNIT_PRECISION], base[MAX_UNIT_PRECISION];
    int c, i;
    boolean minus = FALSE;
    short radix;		/* base 2-16 */

    mp_init(reg, 0);

    i = string_length(digitstr);
    if (i == 0)
	return (10);		/* empty string, assume radix 10 */
    c = digitstr[i - 1];	/* get last char in string */

    switch (c) {		/* classify radix select suffix character */
    case '.':
	radix = 10;
	break;
    case 'H':
    case 'h':
	radix = 16;
	break;
    case 'O':
    case 'o':
	radix = 8;
	break;
    case 'B':			/* caution! 'b' is a hex digit! */
    case 'b':
	radix = 2;
	break;
    default:
	radix = 10;
	break;
    }

    mp_init(base, radix);
    if ((minus = (*digitstr == '-')) != 0)
	digitstr++;
    while ((c = *digitstr++) != 0) {
	if (c == ',')
	    continue;		/* allow commas in number */
	c = ctox(c);
	if ((c < 0) || (c >= radix))
	    break;		/* scan terminated by any non-digit */
	mp_mult(temp, reg, base);
	mp_move(reg, temp);
	mp_init(temp, c);
	mp_add(reg, temp);
    }
    if (minus)
	mp_neg(reg);
    return (radix);
}				/* str2reg */
示例#4
0
文件: mout.c 项目: andreiw/polaris
static int
m_in(MINT *a, short b, FILE *f)
{
	MINT x, y, ten;
	int sign, c;
	short qten, qy;

	_mp_xfree(a);
	sign = 1;
	ten.len = 1;
	ten.val = &qten;
	qten = b;
	x.len = 0;
	y.len = 1;
	y.val = &qy;
	while ((c = getc(f)) != EOF)
	switch (c) {

	case '\\':
		(void) getc(f);
		continue;
	case '\t':
	case '\n':
		a->len *= sign;
		_mp_xfree(&x);
		return (0);
	case ' ':
		continue;
	case '-':
		sign = -sign;
		continue;
	default:
		if (c >= '0' && c <= '9') {
			qy = c - '0';
			mp_mult(&x, &ten, a);
			mp_madd(a, &y, a);
			_mp_move(a, &x);
			continue;
		} else {
			(void) ungetc(c, stdin);
			a->len *= sign;
			return (0);
		}
	}
	return (EOF);
}
示例#5
0
文件: old_mp.c 项目: andreiw/polaris
void mult(MINT *a, MINT *b, MINT *c) { mp_mult(a, b, c); }