示例#1
0
void BTreeBase::pruneTree(BTreeNode *root, bool /*conditionalRoot*/)
{
	Traverser t(root);
	
	t.descendLeftwardToTerminal();
	bool done = false;
	while(!done)
	{
	//t.descendLeftwardToTerminal();
	if( t.current()->parent() )
	{
		if( t.oppositeNode()->hasChildren() ) pruneTree(t.oppositeNode());
	}
	
	t.moveToParent();
	if( !t.current()->hasChildren() )
	{
		//if(t.current() == t.root()) done = true;
		if(!t.current()->parent()) done = true;
		continue;
	}

	BTreeNode *l = t.current()->left();
	BTreeNode *r = t.current()->right();
	BTreeNode *n = 0;
	BTreeNode *z = 0;
	

	// Deal with situations where there are two constants so we want
	// to evaluate at compile time
	if( (l->type() == number && r->type() == number) ) // && !(t.current()==root&&conditionalRoot) )
	{
		if(t.current()->childOp() == Expression::division && r->value() == "0" ) 
		{
			t.current()->setChildOp(Expression::divbyzero);
			return;
		}
		QString value = QString::number(Parser::doArithmetic(l->value().toInt(),r->value().toInt(),t.current()->childOp()));
		t.current()->deleteChildren();
		t.current()->setChildOp(Expression::noop);
		t.current()->setType(number);
		t.current()->setValue(value);
	}
	
	// Addition and subtraction
	else if(t.current()->childOp() == Expression::addition || t.current()->childOp() == Expression::subtraction)
	{
	// See if one of the nodes is 0, and set n to the node that actually has data,
	// z to the one containing zero.
	bool zero = false;
	if( l->value() == "0" )
	{
		zero = true;
		n = r;
		z = l;
	}
	else if( r->value() == "0" )
	{
		zero = true;
		n = l;
		z = r;
	}
	// Now get rid of the useless nodes
	if(zero)
	{
		BTreeNode *p = t.current(); // save in order to delete after

		replaceNode(p,n);
		t.setCurrent(n);
		// Delete the old nodes
		delete p;
		delete z;
	}
	}
	
	// Multiplication and division
	else if(t.current()->childOp() == Expression::multiplication || t.current()->childOp() == Expression::division)
	{
	// See if one of the nodes is 0, and set n to the node that actually has data,
	// z to the one containing zero.
	bool zero = false;
	bool one = false;
	if( l->value() == "1" )
	{
		one = true;
		n = r;
		z = l;
	}
	else if( r->value() == "1" )
	{
		one = true;
		n = l;
		z = r;
	}
	if( l->value() == "0" )
	{
		zero = true;
		n = r;
		z = l;
	}
	else if( r->value() == "0" )
	{
		
		// since we can't call compileError from in this class, we have a special way of handling it:
		// Leave the children as they are, and set childOp to divbyzero
		if( t.current()->childOp() == Expression::division )
		{
			t.current()->setChildOp(Expression::divbyzero);
			return; // no point doing any more since we are going to raise a compileError later anyway.
		}
		zero = true;
		n = l;
		z = r;
	}
	// Now get rid of the useless nodes
	if(one)
	{
		BTreeNode *p = t.current(); // save in order to delete after
		replaceNode(p,n);
		t.setCurrent(n);
		// Delete the old nodes
		delete p;
		delete z;
	}
	if(zero)
	{
		BTreeNode *p = t.current();
		p->deleteChildren();
		p->setChildOp(Expression::noop);
		p->setType(number);
		p->setValue("0");
		
	}
	}
	else if( t.current()->childOp() == Expression::bwand || t.current()->childOp() == Expression::bwor || t.current()->childOp() == Expression::bwxor )
	{
	bool zero = false;
	if( l->value() == "0" )
	{
		zero = true;
		n = r;
		z = l;
	}
	else if( r->value() == "0" )
	{
		zero = true;
		n = l;
		z = r;
	}
	// Now get rid of the useless nodes
	if(zero)
	{
		BTreeNode *p = t.current();
		QString value;
		if( p->childOp() == Expression::bwand )
		{
			value = "0";
			p->deleteChildren();
			p->setChildOp(Expression::noop);
			p->setType(number);
		}
		if( p->childOp() == Expression::bwor || p->childOp() == Expression::bwxor )
		{
			value = n->value();
			BTreeNode *p = t.current(); // save in order to delete after
			replaceNode(p,n);
			t.setCurrent(n);
			// Delete the old nodes
			delete p;
			delete z;
		}
		p->setValue(value);
	}
	}
	
	if(!t.current()->parent() || t.current() == root) done = true;
	else
	{

	}
	}
}
示例#2
0
void Expression::compileConditional( const QString & expression, Code * ifCode, Code * elseCode )
{
	if( expression.contains(QRegExp("=>|=<|=!")) )
	{
		mistake( Microbe::InvalidComparison, expression );
		return;
	}
	if( expression.contains(QRegExp("[^=><!][=][^=]")))
	{
		mistake( Microbe::InvalidEquals );
		return;
	}
	// Make a tree to put the expression in.
	BTreeBase *tree = new BTreeBase();
	BTreeNode *root = new BTreeNode();

	// parse the expression into the tree
	buildTree(expression,tree,root,0);
	
	// Modify the tree so it is always at the top level of the form (kwoerpkwoep) == (qwopekqpowekp)
	if ( root->childOp() != equals &&
			root->childOp() != notequals &&
			root->childOp() != gt &&
			root->childOp() != lt &&
			root->childOp() != ge &&
			root->childOp() != le &&
			root->childOp() != pin &&
			root->childOp() != notpin &&
			root->childOp() != read_keypad )
	{
		BTreeNode *newRoot = new BTreeNode();
		
		BTreeNode *oneNode = new BTreeNode();
		oneNode->setChildOp(noop);
		oneNode->setType(number);
		oneNode->setValue("1");
		
		newRoot->setLeft(root);
		newRoot->setRight(oneNode);
		newRoot->setType(unset);
		newRoot->setChildOp(ge);
		
		tree->setRoot(newRoot);
		root = newRoot;
	}
	// compile the tree into assembly code
	tree->setRoot(root);
	tree->pruneTree(tree->root(),true);
	
	// We might have just a constant expression, in which case we can just always do if or else depending
	// on whether it is true or false.
	if( root->childOp() == noop )
	{
		if( root->value().toInt() == 0 )
			m_pic->mergeCode( elseCode );
		else
			m_pic->mergeCode( ifCode );
		return;
	}
	
	// traverse tree with argument conditionalRoot true
	// so that 3 == x gets integrated with code for if, repeat until etc...
	m_ifCode = ifCode;
	m_elseCode = elseCode;
	traverseTree(tree->root(),true);
	
	// Note deleting the tree deletes all nodes, so the root
	// doesn't need deleting separately.
	delete tree;
}