示例#1
0
void Cholesky (const DenseMatrix & a,
	       DenseMatrix & l, Vector & d)
{
  // Factors   A = L D L^T

  double x;

  int i, j, k;
  int n = a.Height();
  
  //  (*testout) << "a = " << a << endl;

  l = a;

  for (i = 1; i <= n; i++)
    {
      for (j = i; j <= n; j++)
	{
	  x = l.Get(i, j);

	  for (k = 1; k < i; k++)
	    x -= l.Get(i, k) * l.Get(j, k) * d.Get(k); 
	  
	  if (i == j)
	    {
	      d.Elem(i) = x;
	    }
	  else
	    {
	      l.Elem(j, i) = x / d.Get(k);
	    }
	}
    }

  for (i = 1; i <= n; i++)
    {
      l.Elem(i, i) = 1;
      for (j = i+1; j <= n; j++)
	l.Elem(i, j) = 0;
    }

  /*
  // Multiply:
  (*testout) << "multiplied factors: " << endl;
  for (i = 1; i <= n; i++)
    for (j = 1; j <= n; j++)
      {
	x = 0;
	for (k = 1; k <= n; k++)
	  x += l.Get(i, k) * l.Get(j, k) * d.Get(k);
	(*testout) << x << " ";
      }
  (*testout) << endl;
  */
}
示例#2
0
void OptimalActiveSetW(DenseMatrix<T>& W,         // m x 2
                       const DenseMatrix<T>& HHt, // 2 x 2
                       const DenseMatrix<T>& AHt) // m x 2
{
    // Remove negative entries in each of the m rows of matrix W, but
    // do so in a manner that minimizes the overall objective function. 
    // Each row can be considered in isolation.
    //
    // The problem for each row i of W, w = W(i,:), is as follows:
    //
    //     min_{w>=0} |wH - a|^2
    //
    // This is minimized when w'* = Ha'/(hh'), or w* = aH'/(hh').  
    // Expressed in terms of the individual elements, this becomes:
    //
    //    w*[0] = ah'[0] / (h[0]h'[0])
    //    w*[1] = ah'[1] / (h[1]h'[1])

    // If both elements of w* are nonnegative, this is the optimal solution.  
    // If any elements are negative, the Rank2 algorithm is used to adjust
    // their values.
    
    int height = W.Height();
    
    const T hht_00 = HHt.Get(0,0);
    const T hht_11 = HHt.Get(1,1);
    const T inv_hht_00 = T(1.0) / hht_00;
    const T inv_hht_11 = T(1.0) / hht_11;
    const T sqrt_hht_00 = sqrt(hht_00);
    const T sqrt_hht_11 = sqrt(hht_11);

    for (int i=0; i<height; ++i)
    {
        T v1 = AHt.Get(i, 0) * inv_hht_00;
        T v2 = AHt.Get(i, 1) * inv_hht_11;
        T vv1 = v1 * sqrt_hht_00;
        T vv2 = v2 * sqrt_hht_11;

        if (vv1 >= vv2)
            v2 = T(0);
        else
            v1 = T(0);

        if ( (W.Get(i, 0) <= T(0)) || (W.Get(i, 1) <= T(0)))
        {
            W.Set(i, 0, v1);
            W.Set(i, 1, v2);
        }
    }
}
示例#3
0
void OptimalActiveSetH(DenseMatrix<T>& H,         // 2 x n
                       const DenseMatrix<T>& WtW, // 2 x 2
                       const DenseMatrix<T>& WtA) // 2 x n
{
    // Remove negative entries in each of the n columns of matrix H, but
    // do so in a manner that minimizes the overall objective function. 
    // Each column can be considered in isolation.
    //
    // The problem for each column i of H, h = H(:,i),  is as follows:
    //
    //     min_{h>=0} |Wh - a|^2
    //
    // This is minimized when h* = w'a / (w'w).  Expressed in terms of the
    // individual elements, this becomes:
    //
    //    h*[0] = w[0]'a / (w[0]'w[0])
    //    h*[1] = w[1]'a / (w[1]'w[1])

    // If both elements of h* are nonnegative, this is the optimal solution.  
    // If any elements are negative, the Rank2 algorithm is used to adjust
    // their values.
    
    int width = H.Width();
    
    const T wtw_00 = WtW.Get(0,0);
    const T wtw_11 = WtW.Get(1,1);
    const T inv_wtw_00 = T(1.0) / wtw_00;
    const T inv_wtw_11 = T(1.0) / wtw_11;
    const T sqrt_wtw_00 = sqrt(wtw_00);
    const T sqrt_wtw_11 = sqrt(wtw_11);

    for (int i=0; i<width; ++i)
    {
        T v1 = WtA.Get(0,i) * inv_wtw_00;
        T v2 = WtA.Get(1,i) * inv_wtw_11;
        T vv1 = v1 * sqrt_wtw_00;
        T vv2 = v2 * sqrt_wtw_11;

        if (vv1 >= vv2)
            v2 = T(0);
        else
            v1 = T(0);

        if ( (H.Get(0,i) <= T(0)) || (H.Get(1,i) <= T(0)))
        {
            H.Set(0, i, v1);
            H.Set(1, i, v2);
        }
    }
}
示例#4
0
void MakeDiagonallyDominant(DenseMatrix<T>& M)
{
    // Make the diagonal element larger than the row sum, to ensure that
    // the matrix is nonsingular.  All entries in the matrix are nonnegative, 
    // so no absolute values are needed.

    for (int r=0; r<M.Height(); ++r)
    {
        T row_sum = 0.0;
        for (int c=0; c<M.Width(); ++c)
            row_sum += M.Get(r, c);
        M.Set(r, r, row_sum + T(1));
    }
}
示例#5
0
bool HasNaNs(const DenseMatrix<T>& M)
{
    // returns true if any matrix element is NaN

    int height = M.Height();
    int width  = M.Width();
    for (int c=0; c<width; ++c)
    {
        for (int r=0; r<height; ++r)
        {
            T elt = M.Get(r, c);
            if (std::isnan(elt))
                return true;
        }
    }

    return false;
}
示例#6
0
bool SystemSolveH(DenseMatrix<T>& X, // H    2 x n
                  DenseMatrix<T>& A, // WtW  2 x 2
                  DenseMatrix<T>& B) // WtA  2 x n
{
    // This function solves the system A*X = B for X.  The columns of X and B
    // are treated as separate subproblems.  Each subproblem can be expressed
    // as follows, for column i of X and B (the ' means transpose):
    //
    //              A * [x0  x1]' = [b0  b1]'
    //
    // The solution proceeds by transforming matrix A to upper triangular form
    // via a fast Givens rotation.  The resulting triangular system for the 
    // two unknowns in each column of X is then solved by backsubstitution.
    //
    // The fast Givens method relies on the fact that matrix A can be 
    // expressed as the product of a diagonal matrix D and another matrix Y,
    // and that this form is preserved under the rotation.  If J is the 
    // Givens rotation matrix, then:
    //
    //           AX    = B
    //          JAX    = JB        J is the Givens rotation matrix
    //         (JA)X   = JB        letting A = D1Y1
    //        (JD1Y1)X = JB
    //        (D2Y2)X  = JB
    //
    // The matrix D1 is the identity matrix, and the matrix Y1 is the
    // original matrix A.  The matrix J has the form [c -s; c s] in Matlab
    // notation.  NOTE: with this convention, the tangent has a minus sign:
    //
    //            t = -A(1, 0) / A(0, 0)
    //
    // Matrix A has the form [a b; c d], and after the rotation it is
    // transformed to [a2 b2; 0 d2].
    //
    // There are two forms for the D2 and Y2 matrices, depending on whether
    // cosines or sines are 'factored out'.  If |A00| >= |A01|, then the
    // upper left element is factored out and the 'cosine' formulation is
    // used.  If |A00| < |A01|, then the upper right element is factored
    // out and the 'sine' formulation is used.
    //
    // A general reference for this code is the paper 'Fast Plane Rotations
    // with Dynamic Scaling', by A. Anda and H. Park, SIAM Journal on Matrix
    // Analysis and Applications, Vol 15, no. 1, pp. 162-174, Jan. 1994.

    int n = B.Width();
    T abs_A00 = std::abs(A.Get(0, 0));
    T abs_A01 = std::abs(A.Get(0, 1));
    const T epsilon = std::numeric_limits<T>::epsilon();

    if ( (abs_A00 < epsilon) && (abs_A01 < epsilon))
    {
        std::cerr << "SystemSolveH: singular matrix" << std::endl;
        return false;
    }

    T a2, b2, d2, e2, f2, inv_a2, inv_d2, x_1;
    if (abs_A00 >= abs_A01)
    {   
        // use 'cosine' formulation; t is the tangent
        T t = -A.Get(1,0) / A.Get(0,0);
        a2 = A.Get(0,0) - t*A.Get(1,0);
        b2 = A.Get(0,1) - t*A.Get(1,1);
        d2 = A.Get(1,1) + t*A.Get(0,1);

        // precompute 1/a2 and 1/d2 to avoid repeated division
        inv_a2 = T(1.0) / a2;
        inv_d2 = T(1.0) / d2;

        // a2 is guaranteed to be positive
        if (std::abs(d2/a2) < epsilon)
            return false;

        // solve the upper triangular systems by backsubstitution
        for (int i=0; i<n; ++i)
        {
            e2 = B.Get(0,i) - t*B.Get(1,i);
            f2 = B.Get(1,i) + t*B.Get(0,i);
            x_1 = f2 * inv_d2;
            X.Set(1, i, x_1);
            X.Set(0, i, (e2 - b2*x_1)*inv_a2);
        }
    }
    else
    {
        // use 'sine' formulation; ct is the cotangent
        T ct = -A.Get(0,0) / A.Get(1,0);
        a2 = -A.Get(1,0) + ct*A.Get(0,0);
        b2 = -A.Get(1,1) + ct*A.Get(0,1);
        d2 =  A.Get(0,1) + ct*A.Get(1,1);

        // precompute 1/a2 and 1/d2 to avoid repeated division
        inv_a2 = T(1.0) / a2;
        inv_d2 = T(1.0) / d2;

        // a2 is guaranteed to be positive
        if (std::abs(d2/a2) < epsilon)
            return false;

        // solve the upper triangular systems by backsubstitution
        for (int i=0; i<n; ++i)
        {
            e2 = -B.Get(1,i) + ct*B.Get(0,i);
            f2 =  B.Get(0,i) + ct*B.Get(1,i);
            x_1 = f2 * inv_d2;
            X.Set(1, i, x_1);
            X.Set(0, i, (e2 - b2*x_1) * inv_a2);
        }
    }

    return true;
}
示例#7
0
bool SystemSolveW(DenseMatrix<T>& X,  // m x 2
                  DenseMatrix<T>& A,  // 2 x 2
                  DenseMatrix<T>& B)  // m x 2
{
    // Solve XA = B; use the code from the previous solver, but transpose
    // everything and change t to -t.

    const T eps = std::numeric_limits<double>::epsilon();
    int m = B.Height();

    if (std::abs(A.Get(0,0)) < eps && std::abs(A.Get(0,1)) < eps) 
    {
        std::cerr << "SystemSolveW: singular matrix" << std::endl;
        return false;
    }

    T a2, b2, d2, e2, f2, x_1;
    T inv_a2, inv_d2;

    if (std::abs(A.Get(0,0)) >= std::abs(A.Get(0, 1))) 
    {
        // use 'cosine' formulation; t is the tangent
        T t = A.Get(0, 1) / A.Get(0,0);
        a2 = A.Get(0,0) + t*A.Get(0,1);
        b2 = A.Get(1,0) + t*A.Get(1,1);
        d2 = A.Get(1,1) - t*A.Get(1,0);

        // precompute 1/a2 and 1/d2 to avoid repeated division
        inv_a2 = T(1.0) / a2;
        inv_d2 = T(1.0) / d2;

        // a2 is guaranteed to be positive
        if (std::abs(d2/a2) < eps)
            return false;

        // solve the upper triangular systems by backsubstitution
        for (int i=0; i<m; ++i)
        {
            e2 = B.Get(i,0) + t*B.Get(i,1);
            f2 = B.Get(i,1) - t*B.Get(i,0);
            x_1 = f2 * inv_d2;
            X.Set(i, 1, x_1);
            X.Set(i, 0, (e2 - b2*x_1)*inv_a2);
        }
    } 
    else 
    {
        // use 'sine' formulation; ct is the cotangent
        T ct = A.Get(0,0) / A.Get(0,1);
        a2 = -A.Get(0,1) - ct*A.Get(0,0);
        b2 = -A.Get(1,1) - ct*A.Get(1,0);
        d2 =  A.Get(1,0) - ct*A.Get(1,1);

        // precompute 1/a2 and 1/d2 to avoid repeated division
        inv_a2 = T(1.0) / a2;
        inv_d2 = T(1.0) / d2;

        // a2 is guaranteed to be positive
        if (std::abs(d2/a2) < eps)
            return false;

        // solve the upper triangular systems by backsubstitution
        for (int i=0; i<m; ++i)
        {
            e2 = -B.Get(i,1) - ct*B.Get(i,0);
            f2 =  B.Get(i,0) - ct*B.Get(i,1);
            x_1 = f2 * inv_d2;
            X.Set(i, 1,  x_1);
            X.Set(i, 0, (e2 - b2*x_1) * inv_a2);
        }
    }

    return true;
}