C++ (Cpp) Utilitario::IntToString示例

示例#1

文件： Context.cpp 项目： lince/ginga-recommender

					string Context::generateSql() {
						Utilitario* util = Utilitario::getInstance();
						string cId;
						if(context == NULL)
							cId = util->IntToString(0);
						else
							cId = util->IntToString(context->getIdContext());
						return "insert into context (id, idSContext, idDocument) values ('" + id + "', " + cId + ", " + util->IntToString(document->getIdDocument()) + ");";
					}

示例#2

文件： Document.cpp 项目： lince/ginga-recommender

					string Document::generateSql() {
						Utilitario* util = Utilitario::getInstance();
						return "insert into document (id, idNclStateMachine) values ('" + id + "', " + util->IntToString(nclStateMachine->getIdNclStateMachine()) + ");";
					}

示例#3

文件： User.cpp 项目： lince/ginga-srpp

				    string User::generateSql5(int id) {
						Utilitario* util = Utilitario::getInstance();
						return "select idRefUser, genre, zip, age from users where idUser = "******" ;";
				    }			    

示例#4

文件： Volume.cpp 项目： lince/ginga-recommender

					string Volume::generateSql() {
						Utilitario* util = Utilitario::getInstance();
						return "insert into volume (level, mute) values (" + util->IntToString(level) + ", " + util->IntToString(mute) + ");";
					}