示例#1
0
 long index(types::list<T> &seq, T const &x)
 {
   long index_value = seq.index(x);
   if (index_value == seq.size())
     throw types::ValueError(__builtin__::anonymous::str(x) +
                             " is not in list");
   return index_value;
 }
示例#2
0
 types::none_type insert(types::list<T> &seq, long n, F &&value)
 {
   n = n % (1 + seq.size()); // +1 because we want to be able to insert at
                             // the end of seq
   if (n < 0)
     n += seq.size();
   seq.insert(n, std::forward<F>(value));
   return __builtin__::None;
 }
示例#3
0
文件: select.hpp 项目: LuisBL/pythran
 types::ndarray<typename U::type, U::value>
 select(types::list<T> const &condlist, types::list<U> const &choicelist,
        typename U::dtype _default)
 {
   constexpr size_t N = U::value;
   auto &&choicelist0_shape = choicelist[0].shape();
   types::ndarray<T, N> out(choicelist0_shape, _default);
   types::ndarray<T, N> selected(choicelist0_shape(), false);
   long size = selected.flat_size();
   for (long i = 0; i < condlist.size() && size != 0; i++)
     size =
         _select(choicelist[i].begin(), choicelist[i].end(), out.begin(),
                 selected.begin(), condlist.begin(), size, utils::int_<N>());
   return out;
 }
示例#4
0
文件: select.hpp 项目: LuisBL/pythran
 types::ndarray<T, N>
 select(types::list<types::ndarray<U, N>> const &condlist,
        types::list<types::ndarray<T, N>> const &choicelist, T _default)
 {
   types::ndarray<T, N> out(choicelist[0].shape(), _default);
   for (long i = 0; i < out.flat_size(); ++i)
     for (long j = 0; j < condlist.size(); ++j)
       if (condlist[j].buffer[i]) {
         out.buffer[i] = choicelist[j].buffer[i];
         break;
       }
   return out;
 }
示例#5
0
 /*  Generate next permutation
  *
  *  If the size of the permutation is smaller than the size of the
  *  pool, we may have to iterate multiple times
  */
 permutations_iterator& operator++()
 {
     if(_size!=pool.size()) {
         // Slow path, the iterator is a "view" of a prefix smaller
         // than the the pool size
         // FIXME a better implementation would be to avoid
         // std::next_permutation, but only in the slow path
         types::list<int> prev_permut(curr_permut.begin(),
                 curr_permut.begin()+_size);
         types::list<int> new_permut;
         while((end = std::next_permutation(curr_permut.begin(),
                         curr_permut.end()))) {
             // Check if the prefix of the new permutation is
             // different of the previous one
             types::list<int> new_permut(curr_permut.begin(),
                     curr_permut.begin()+_size);
             if(!(prev_permut==new_permut)) break;
         }
     } else {
         end = std::next_permutation(curr_permut.begin(),
                 curr_permut.end());
     }
     return *this;
 }
示例#6
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 types::none_type append(types::list<T> &seq, F &&value)
 {
   seq.push_back(std::forward<F>(value));
   return __builtin__::None;
 }
示例#7
0
文件: sort.hpp 项目: OnlySang/pythran
 types::none_type sort(types::list<T> &seq) {
     std::sort(seq.begin(),seq.end());
     return __builtin__::None;
 }
示例#8
0
 long index(types::list<T> &seq, T const& x) {
     return seq.index(x);
 }
示例#9
0
 types::none_type reverse(types::list<T> &seq) {
     std::reverse(seq.begin(),seq.end());
     return __builtin__::None;
 }
示例#10
0
 bool operator==(permutations_iterator const& other) const
 {
     if(other.end != end)
         return false;
     return std::equal(curr_permut.begin(), curr_permut.end(), other.curr_permut.begin());
 }