int main()
{
StackMin min;
ElemType tmp;
cin >> tmp;
while (tmp != -1)
{
min.Push(tmp);
cin >> tmp;
}
min.Pop();
cout << min.Min() << endl;
return 0;
}
int main()
{
//3.2 Stack Min: How would you design a stack which, in addition to push and pop, has a function min
//which returns the minimum element ? Push, pop and min should all operate in O(1) time.
//Hints : #27, #59, #78
cout << endl;
cout << "StackMin: " << endl;
StackMin MyMinStack;
cout << MyMinStack.IsEmpty() << endl;
MyMinStack.Push(25);
cout << MyMinStack.IsEmpty() << endl;
MyMinStack.Push(30);
MyMinStack.Push(15);
MyMinStack.Push(5);
MyMinStack.Print();
cout << "Peek: " << MyMinStack.Peek() << endl;
cout << "Current Minimum: " << MyMinStack.Min() << endl;
cout << "Pop: " << MyMinStack.Pop() << endl;
cout << "Current Minimum: " << MyMinStack.Min() << endl;
cout << "Pop: " << MyMinStack.Pop() << endl;
cout << "Current Minimum: " << MyMinStack.Min() << endl;
cout << "Peek: " << MyMinStack.Peek() << endl;
MyMinStack.Print();
//3.4 Queue via Stacks : Implement a MyQueue class which implements a queue using two stacks.
//Hints : #98, #114
cout << endl;
cout << "QueueViaStacks: " << endl;
QueueViaStacks MyQueue;
MyQueue.Enqueue(15);
MyQueue.Enqueue(20);
MyQueue.Enqueue(25);
cout << "MyQueue£º 15 20 25.\n";
cout << "Size of my QViaStacks: " << MyQueue.Size() << endl;
cout << "Peek my QViaStacks: " << MyQueue.Peek()<<endl;
MyQueue.Dequeue();
cout << "Dequeue and Peek: " << MyQueue.Peek() << endl;
cout << "Size of my QViaStacks: " << MyQueue.Size() << endl;
MyQueue.Enqueue(35);
cout << "Dequeue and Peek: " << MyQueue.Peek() << endl;
cout << "Size of my QViaStacks: " << MyQueue.Size() << endl;
MyQueue.Dequeue();
cout << "Dequeue and Peek: " << MyQueue.Peek() << endl;
cout << "Size of my QViaStacks: " << MyQueue.Size() << endl;
//3.4 In the classic problem of the Towers of Hanoi, you have 3 rods and N disks of different
//sizes which can slide onto any tower.The puzzle starts with disks sorted in ascending
//order of size from top to bottom(e.g., each disk sits on top of an even larger one).You
//have the following constraints :
//(A)Only one disk can be moved at a time.
//(B)A disk is slid off the top of one rod onto the next rod.
//(C)A disk can only be placed on top of a larger disk.
//Write a program to move the disks from the first rod to the last using Stacks.
cout << endl;
cout << "TowerOfHanoi: " << endl;
TowerOfHanoi MyTower(6);
MyTower.SolveTOH();
//3.5 Sort Stack : Write a program to sort a stack such that the smallest items are on the top.You can use
//an additional temporary stack, but you may not copy the elements into any other data structure
//(such as an array).The stack supports the following operations : push, pop, peek, and is Empty.
//Hints : # 15, #32, #43
cout << endl;
cout << "Sort Stack: 4 3 1 5 2" << endl;
stack<int> InputStack;
InputStack.push(2);
InputStack.push(5);
InputStack.push(1);
InputStack.push(3);
InputStack.push(4);
stack<int> result = Sort(InputStack);
cout << "Sorted Stack: \n";
while(!result.empty())
{
cout << result.top()<<" ";
result.pop();
}
getchar();
return 0;
}