Example #1
0
SBasis toSBasis(SBasisOf<double> const &f){
    SBasis result(f.size(), Linear());
    for (unsigned i=0; i<f.size(); i++){
        result[i] = Linear(f[i][0],f[i][1]);
    }
    return result;
}
OptInterval bounds_fast(const SBasisOf<double> &sb, int order) {
#else
OptInterval bounds_fast(const SBasis &sb, int order) {
#endif
    Interval res(0,0); // an empty sbasis is 0.

    for(int j = sb.size()-1; j>=order; j--) {
        double a=sb[j][0];
        double b=sb[j][1];

        double v, t = 0;
        v = res[0];
        if (v<0) t = ((b-a)/v+1)*0.5;
        if (v>=0 || t<0 || t>1) {
            res[0] = std::min(a,b);
        }else{
            res[0]=lerp(t, a+v*t, b);
        }

        v = res[1];
        if (v>0) t = ((b-a)/v+1)*0.5;
        if (v<=0 || t<0 || t>1) {
            res[1] = std::max(a,b);
        }else{
            res[1]=lerp(t, a+v*t, b);
        }
    }
    if (order>0) res*=pow(.25,order);
    return res;
}
OptInterval bounds_local(const SBasisOf<double> &sb, const OptInterval &i, int order) {
#else
OptInterval bounds_local(const SBasis &sb, const OptInterval &i, int order) {
#endif
    double t0=i->min(), t1=i->max(), lo=0., hi=0.;
    for(int j = sb.size()-1; j>=order; j--) {
        double a=sb[j][0];
        double b=sb[j][1];

        double t = 0;
        if (lo<0) t = ((b-a)/lo+1)*0.5;
        if (lo>=0 || t<t0 || t>t1) {
            lo = std::min(a*(1-t0)+b*t0+lo*t0*(1-t0),a*(1-t1)+b*t1+lo*t1*(1-t1));
        }else{
            lo = lerp(t, a+lo*t, b);
        }

        if (hi>0) t = ((b-a)/hi+1)*0.5;
        if (hi<=0 || t<t0 || t>t1) {
            hi = std::max(a*(1-t0)+b*t0+hi*t0*(1-t0),a*(1-t1)+b*t1+hi*t1*(1-t1));
        }else{
            hi = lerp(t, a+hi*t, b);
        }
    }
    Interval res = Interval(lo,hi);
    if (order>0) res*=pow(.25,order);
    return res;
}
Example #4
0
SBasisOf<T> integraaal(SBasisOf<T> const &c){
    SBasisOf<T> a;
    a.resize(c.size() + 1, LinearOf<T>(T(0.),T(0.)));

    for(unsigned k = 1; k < c.size() + 1; k++) {
        T ahat = (c[k-1][0]-c[k-1][1])/(2*k);
        a[k] = LinearOf<T>(ahat);
    }

    T aTri = T(0.);
    for(int k = c.size()-1; k >= 0; k--) {
        aTri = (HatOf<T>(c[k]).d + (k+1)*aTri/2)/(2*k+1);
        a[k][0] -= aTri/2;
        a[k][1] += aTri/2;
    }
    //a.normalize();
    return a;
}
Example #5
0
SBasisOf<SBasisOf<double> > integral(SBasisOf<SBasisOf<double> > const &f, unsigned var){
    //variable of f = 1, variable of f's coefficients = 0. 
    if (var == 1) return integraaal(f);
    SBasisOf<SBasisOf<double> > result;
    for(unsigned i = 0; i< f.size(); i++) {
        //result.push_back(LinearOf<SBasisOf<double> >( integral(f[i][0]),integral(f[i][1])));
        result.push_back(LinearOf<SBasisOf<double> >( integraaal(f[i][0]),integraaal(f[i][1])));
    }
    return result;
}
Example #6
0
SBasisOf<double> compose(SBasisOf<SBasisOf<double> > const &f, 
                         SBasisOf<double> const &x, 
                         SBasisOf<double> const &y){
    SBasisOf<double> y0 = -y + LinearOf<double>(1,1);
    SBasisOf<double> s = multiply(y0,y);
    SBasisOf<double> r;

    for(int i = f.size()-1; i >= 0; i--) {
        r = s*r + compose(f[i][0],x)*y0 + compose(f[i][1],x)*y;
    }
    return r;
}
Example #7
0
SBasisOf<T> multi_compose(SBasisOf<double> const &f, SBasisOf<T> const &g ){

    //assert( f.input_dim() <= g.size() );
    
    SBasisOf<T> u1 = g;
    SBasisOf<T> u0 = -g + LinearOf<SBasisOf<double> >(SBasisOf<double>(LinearOf<double>(1,1)));
    SBasisOf<T> s = multiply(u0,u1);
    SBasisOf<T> r;

    for(int i = f.size()-1; i >= 0; i--) {
        r = s*r + f[i][0]*u0 + f[i][1]*u1;
    }
    return r;
}