Exemplo n.º 1
0
    template<class V> void print_container(V& container, bitset<MAX_BITS_SIZE>& flag, bool reverse, bool is_servercmp)
    {
      if (reverse)
      {
        flag.flip();
      }
      typename V::iterator it = container.begin();

      if (!is_servercmp) // print different block
      {
        int32_t count = static_cast<int32_t> (flag.count());
        for (int32_t i = 0, c=0; (it != container.end()) && (count > 0); i++, it++)
        {
          if (flag.test(i))
          {
            cout << *it ;
            if((++c) % 20 == 0)
              cout<<"\n";
            else
              cout<<" ";
            count--;
          }
        }
        printf(" [%d]\n", static_cast<int32_t>((flag.count() - count)));
      }
      else
      {
        for (int32_t i = 0; it != container.end(); i++, it++)
        {
          printf("%23s%c", tbsys::CNetUtil::addrToString(*it).c_str(),
              suffix(flag[i]));
        }
        printf(" [%zd]\n", container.size());
      }
    }
Exemplo n.º 2
0
 void dfs(vector<vector<int>>& vv, bitset<maxNUM>& bt, int pos, int n, int k) {
     if(pos > n || bt.count() > k) return ;
     if(bt.count() == k && pos == n){
         string ans = bt.to_string();
         vector<int> vt;
         vt.clear();
         for(int i = 0; i < n; i++) {
             if(ans[i] == '1') vt.push_back(i + 1);
         }
         vv.push_back(vt);
         return ;
     }
     bt.flip(maxNUM - pos - 1);
     dfs(vv, bt, pos + 1, n, k);
     bt.flip(maxNUM - pos - 1);
     dfs(vv, bt, pos + 1, n, k);
 }
Exemplo n.º 3
0
void sieve()
{
    p.flip();
    p[0] = p[1] = 0;
    for(int i=2; i*i<MAX; i++)
        if( p[i] )
            for(int j=i*i; j<MAX; j+=i)
                p[j] = 0;
}
Exemplo n.º 4
0
void sieve()
{
  is_prime.flip();

  for(int n = 3; n < SQRT_N; n += 2)
    if(is_prime[n>>1])
      for(int j = n * n; j < MAX_N; j += (n<<1))
        is_prime[j>>1] = false;
  is_prime[0] = false;
}
void sieve(){
	isp.reset();
	isp.flip();
	isp.set(0,false);
	isp.set(1,false);
	int i,j;
	rep(i,2,1000)
		if(isp[i])
			repdf(j,2*i,1000000,i)isp.set(j,false);
}
Exemplo n.º 6
0
void populatePrime()  // seive of eratosthenes
{
	isPrime.reset();
	isPrime.flip();
	isPrime[0] = isPrime[1] = 0;
	for(int i=2; i*i<=MAX; i++) 
		if(isPrime[i]) 
			for(int j=i*i; j<MAX; j = j+i) 
				isPrime[j] = 0;
}
Exemplo n.º 7
0
//Returns the result N after running PQ through all the gates
bitset<30> Circuit::runGates(bitset<30> pq)
{
    for(int i=0;i<gates.size();++i)
    {
        if(gates[i].noControllers())
        {
            pq.flip(gates[i].getN());
            flipped[i] = 1;
        }
        else
        {
            int flip = 1;
            vector<int> temp = gates[i].getControllers();
            for(int j=0;j<temp.size();++j)
            {
                if(flip)
                {
                    if(gates[i].getInverted())
                    {
                        if(pq[temp[j]])
                        {
                            flip = 0;
                        }
                    }
                    else
                    {
                        if(!(pq[temp[j]]))
                        {
                            flip = 0;
                        }
                    }
                }
            }
            if(flip)
            {
                pq.flip(gates[i].getN());
                flipped[i] = 1;
            }
        }
    }
    return pq;
}
Exemplo n.º 8
0
bitset<100> press ( int button, bitset<100> lamps, int N ) {
	if ( button == 1 ) return lamps.flip();

	bitset<100> mask;
	int i= (button == 3) ? 1 : 0,
		leap = (button == 4) ? 3 : 2;

	for ( ; i < N; i+= leap) mask[100-i-1]= 1;

	return lamps^mask;
}
Exemplo n.º 9
0
void gen_sieve() {
	prime.reset();
	prime.flip();
	prime.set(0, false);
	prime.set(1, false);
	for (size_t i = 2; i <= primen; ++i)
		if (prime.test(i)) {
			for (size_t j = i * i; j <= primen; j += i)
				prime.set(j, false);
		}
}
void sieveGen(){
    sieve.flip();
    sieve.reset(0);
    sieve.reset(1);
    for( int k = 2; k <= OM; k++ )
        if(sieve.test(k)){
            pl.push_back(k);
            if(k <= sqrt(OM))
            for(int i = k + k; i <= OM; i += k )
                sieve.reset(i);
            }
}
Exemplo n.º 11
0
inline void SieveOfAtkin(const int &largest) {
    int square;

    for (int i = 2; i < largest; ++i) primes[i] = false;
    primes.set(0, false);
    primes.set(1, false);
    primes.set(2, true);
    primes.set(3, true);
    //Sieve Of Atkin
    int n, nmod12;
    for (int x = 1; x <= 2236; ++x) { //x till root/2
        for (int y = 1; y <= 4472; y += 2) { //odd y
            n = 4*x*x + y*y;
            nmod12 = n%12;
            if(n < largest && (nmod12 == 1 || nmod12 == 5)) primes.flip(n);
        }
    }

    for (int x = 1; x <= 4472; ++x) {
        for (int y = 1; y <= 4472; ++y) {
            n = 3*x*x + y*y;
            nmod12 = n%12;
            if(n < largest && (nmod12 == 7)) primes.flip(n);

            n = 3*x*x - y*y;
            nmod12 = n%12;
            if(x > y && n < largest && (nmod12 == 11)) primes.flip(n);
        }
    }

    //Eliminate by Sieve
    for (int i = 5; i <= 4472; ++i) {
        if(primes.test(i)) {
            square = i * i;
            for(int j = square; j <= largest; j += square) {
                primes[j] = false;
            }
        }
    }
}
Exemplo n.º 12
0
//Runs the gates in reverse on N in order to return the P and Q values
bitset<30> Circuit::factorGates(bitset<30> n)
{
    for(int i=gates.size()-1;i>=0;--i)
    {
        if(gates[i].noControllers())
        {
            n.flip(gates[i].getN());
        }
        else
        {
            int flip = 1;
            vector<int> temp = gates[i].getControllers();
            for(int j=0;j<temp.size();++j)
            {
                if(flip)
                {
                    if(gates[i].getInverted())
                    {
                        if(n[temp[j]])
                        {
                            flip = 0;
                        }
                    }
                    else
                    {
                        if(!(n[temp[j]]))
                        {
                            flip = 0;
                        }
                    }
                }
            }
            if(flip)
            {
                n.flip(gates[i].getN());
            }
        }
    }
    return n;
}
void sieve(int upper_bound){
	sieve_size = upper_bound;
	bs.reset();
	bs.flip();
	bs[0] = false;
	bs[1] = false;
	for(long long i = 2 ; i <= upper_bound ; i++)
		if(bs[i]){
			for(long long j = i * i ; j <= upper_bound ; j += i)
				 bs[j] = false;
			primes.push_back(i);
		}
}
Exemplo n.º 14
0
void setPrimes()
{
    bset.reset();
    bset.flip();
    bset[1]=0;

    for (size_t i=2;i<LIMIT;i++)
        if (bset.test(i))
             for (size_t j=2; j*i<LIMIT; j++ )
                bset[j*i]=0;
  

}
Exemplo n.º 15
0
Arquivo: 1.cpp Projeto: ak795/acm
void create_prime()
{
    prime.reset();
    prime.flip();
    prime[0]=prime[1]=0;
    for (long long i=2; i<MAX; ++i) {
        if (prime[i]) {
            for (long long j=i*i; j<MAX; j+=i){
                prime[j]=0;
            }
        }
    }
}
Exemplo n.º 16
0
void generate_primes(ll upperbound)
{
	bs.reset();
	bs.flip();
	bs.set(0,false); bs.set(1,false);
	for(ll i = 2; i <= upperbound+1; i++) 
		if(bs.test((i))){
			for(ll  j = i * i ; j <= upperbound+1; j += i)
				bs.set(j,false);
		primes.push_back((int)i);
	}
	
}
Exemplo n.º 17
0
void build_sieve()
{
    sieve = 0;
    sieve.flip();
    sieve[0] = sieve[1] = 0;

    for ( aint n=2; n<MAXSIEVE; ++n ) {
        if ( !sieve[n] )
            continue;
        for ( aint i=2*n; i<MAXSIEVE; i+=n )
            sieve[i] = 0;
    }
}
int main()
{
#ifdef _Rayn
    freopen("in.txt", "r", stdin);
#endif
    int n, q;
    while(scanf("%d", &n) != EOF)
    {
        mp.clear();
        for(int i = 0; i < n; i++) {
            scanf("%s %lld", buf, &byte[i]);
            l = buf;
            while((l = strchr(l, '[')) != NULL)
            {
                r = strchr(l, ']');
                string tag = string(l+1, r);
                mp[tag].set(i, true);
                l = r;
            }
        }
        scanf("%d", &q);
        while (q--) {
            scanf("%s", buf);

            mask.reset();
            mask.flip();

            l = buf;
            while((l = strchr(l, '[')) != NULL)
            {
                r = strchr(l, ']');
                string tag = string(l+1, r);
                if(!mp.count(tag)) {
                    mask.reset();
                    break;
                } else {
                    mask &= mp[tag];
                }
                l = r;
            }
            long long res = 0;
            for (int i = 0; i < n; i++) {
                if (mask[i]) {
                    res += byte[i];
                }
            }
            printf("%lld\n", res);
        }
    }
    return 0;
}
Exemplo n.º 19
0
void mksieve(){
    bs.reset();
    bs.flip();
    bs.set(0, false);
    bs.set(1, false);
    for(ll i = 2; i < sieveUpperBound; i++){
        if(bs.test(i)){
            for(ll j = i*i; j < sieveUpperBound; j += i){
                bs.set(j, false);
            }
            primes.pb(i);
        }
    }
}
Exemplo n.º 20
0
Arquivo: 2.cpp Projeto: ak795/acm
// if bit is 1, then this bit is prime.
void findPrime(bitset<MAX>& bs)
{
    bs.reset();
    bs.flip();
    bs[0] = 0;
    bs[1] = 0;

    for (int i=2; i<=sqrt(MAX-1); i++) {
     	if (bs[i] == 1) {
     	    for (int j=i*i; j<MAX; j+=i) {
     		bs[j] = 0;
     	    }
     	}
    }
}
Exemplo n.º 21
0
Arquivo: 4.cpp Projeto: ak795/acm
// if bit is 1, then this bit is prime.
void findPrime(bitset<MAX2>& prime)
{
    prime.reset();
    prime.flip();
    prime[0] = 0;
    prime[1] = 0;

    for (long long i=2; i<=sqrt(MAX2-1); i++) {
     	if (prime[i] == 1) {
     	    for (long long j=i*i; j<MAX2; j+=i) {
     		prime[j] = 0;
     	    }
     	}
    }
}
Exemplo n.º 22
0
 template<class V> void cmp_disorder_container(const V& container_a, const V& container_b, bitset<MAX_BITS_SIZE>& flag_a, bitset<MAX_BITS_SIZE>& flag_b)
 {
   int index = 0, count = 0;
   typename V::const_iterator iter = container_a.begin();
   for (; iter != container_a.end(); iter++)
   {
     if ((index = find_key(*iter, container_b)) != -1 )
     {
       count++;
       flag_a.set( distance(container_a.begin(), iter) );
       flag_b.set(index);
     }
   }
   for (int i = container_a.size(); i < MAX_BITS_SIZE; i++)
   {
     flag_a.set(i);
   }
   for (int j = container_b.size(); j < MAX_BITS_SIZE; j++)
   {
     flag_b.set(j);
   }
   flag_a.flip();
   flag_b.flip();
 }
Exemplo n.º 23
0
void sieve(ll upperBound,bitset<100007>&_bitset,vector<int>& primes){
    ll sieveSize = upperBound + 1;
    _bitset.reset();
    _bitset.flip(); //set all numbers to 1
    _bitset.set(0,false);
    _bitset.set(1,false);
    for(ll i=2;i<=sieveSize;i++){
        if(_bitset.test((size_t)i)){
            for(ll j=i*i;j<=sieveSize;j+=i)
                _bitset.set((size_t)j,false);
            primes.push_back((int)i);
        }
        
    }
}
Exemplo n.º 24
0
Arquivo: 1.cpp Projeto: ak795/acm
// if bit is 1, then this bit is prime.
void findPrime(bitset<MAX>& prime)
{
    prime.reset();
    prime.flip();
    prime[0] = 0;
    prime[1] = 0;

    for (int i=2; i<=sqrt(MAX-1); i++) {
     	if (prime[i] == 1) {
     	    for (int j=i*i; j<MAX; j+=i) {
     		prime[j] = 0;
     	    }
     	}
    }
}
Exemplo n.º 25
0
void sieve()
{
    int i, j, max = SIEVE_SIZE + 1;
    bs.reset();
    bs.flip();
    bs.set(0, false);
    bs.set(1, true);
    for( i=2; i <= max; i++ )
    {
        if( bs.test(i) == true ) // i é primo, e todos os múltiplos de i nao
        {
            primes.push_back( i );
            for( j = i*i; j <= max; j += i )
            {
                bs.set(j, false);
            }
        }
    }
}
int main() {
    for(int i=0; i<26;i++) {
        scanf("%d", &wczytaj);
        bajtolomeusz.set(wczytaj,1);
        karty_bajt.insert(wczytaj);
    }
    przeciwnik = bajtolomeusz.flip();
    for(int i=1;i<=52;i++) {
        if(przeciwnik[i]==0) continue;
        set<int>::iterator it = karty_bajt.lower_bound(i);
        if(it != karty_bajt.end()) {
            ile_wygranych++;
            karty_bajt.erase(it);
        }else {
            karty_bajt.erase(karty_bajt.begin());
        }
    }
    printf("%d",ile_wygranych);
    return 0;
}
Exemplo n.º 27
0
bitset<28> AddOneBit(bitset<28> bitnum)
//increases the bitset representation by one. Seems to run faster like this
{
    bool ToSwitch;
    for(int i=K;i>=0;i--)
    {
        ToSwitch=true;
        int j=0;
        while(ToSwitch && j<i)
        {
            ToSwitch= (ToSwitch && bitnum.test(j));
            j++;
        }
        if(ToSwitch)
        {
            bitnum.flip(i);
        }
    }
    return bitnum;
}
Exemplo n.º 28
0
static bool isPrime(int n) {
    static bool isInitialized = false;
    static bitset<MAX_INPUT> isPrime;
    if (!isInitialized) {
        isPrime.flip();
        int i=2;
        while (i< MAX_INPUT) {
            for (int j = i+i; j< MAX_INPUT; j+= i) {
                isPrime[j] = false;
            }
            do {
                i++;
            } while (i < MAX_INPUT && !isPrime[i]);
        }
        isPrime[0] = false;
        isPrime[1] = false;
        isInitialized = true;
    }

    return isPrime[n];
}
void sieve(long long upperbound) ///create list of primes from 0 to upperbound
{
    _sieve_size = upperbound + 1;
    bs.reset();
    bs.flip(); /// set all numbers to 1

    bs.set(0, false);
    bs.set(1, false); ///0 and 1 are not prime

    for(long long i = 2; i <= _sieve_size; i++)
    {
        if(bs.test((size_t)i))
        {
            for(long long j = i*i; j <= _sieve_size; j += i)
            {
                bs.set((size_t)j, false);

            }

            primes.push_back((long long)i);
        }
    }
}
Exemplo n.º 30
0
void sieve()
{
  is_prime.flip();

  for(int n = 3; n < SQRT_N; n += 2)
    if(is_prime[n>>1])
      for(int j = n * n; j < MAX_N; j += (n<<1))
        is_prime[j>>1] = false;
  is_prime[0] = false;

  prime_gaps[num_primes] = 0;
  primes[num_primes++] = 2;

  for(int n = 3; n < MAX_N; n += 2)
    if(is_prime[n/2])
    {
      primes[num_primes] = n;
      prime_gaps[num_primes] = primes[num_primes] - primes[num_primes-1];
      //++num_primes;
      DEBUG(printf("primes[%d] = %d prime_gaps[%d] = %d\n", num_primes, primes[num_primes], num_primes, prime_gaps[num_primes]));
      ++num_primes;
    }

}