Exemplo n.º 1
0
bitset::bitset(const bitset& b)
{
    bits.resize(b.size());

    for (unsigned int i = 0; i < b.size(); i++)
        bits[i] = b[i];
}
Exemplo n.º 2
0
/**
 * 计算基因型概率
 * @param geneBit 基因型的二进制表示,其中1表示大写,0表示小写
 * @param r1 左侧重组率
 * @param r2 右侧重组率
 * @param r 整体重组率,默认为0,通过r1和r2计算
 * @param zeta 符合系数,默认为1
 * @return 基因型概率
 */
double calcCross(const bitset<GENE_CP_BIT> geneBit,
		const double r1, const double r2, const double r=0, const double zeta=1) {
	if (geneBit.size()!=GENE_CP_BIT) return 0;

	double r12 = r1*r2*zeta;
	double r0 = r;
	if (r==0) {
		r0 = r1+r2-2*r12;
	}

	// 配子产生的概率,见书105页
	switch(geneBit.to_ulong()) {
		case 0: //M1QM2 000
		case 7: //m1qm2 111
			return (1.0-r1-r2+r12);// `=(1-r1)(1-r2);
		case 1: //M1Qm2 001
		case 6: //m1qM2 110
			return (r2-r12);// `=r2(1-r1);
		case 4: //M1qm2 100
		case 3: //m1QM2 011
			return (r1-r12);// `=r1(1-r2);
		case 5: //M1qM2 101
		case 2: //m1Qm2 010
			return r12;// `=r1*r2;
	}

	return 0;
}
Exemplo n.º 3
0
bool covered(bitset<10> digits){
    for(int i=0;i<digits.size();i++){
        if(digits[i] == false)
            return false;
    }

    return true;
}
Exemplo n.º 4
0
  // restituisce la posizione del nodo i-esimo in preordine
    inline unsigned int preorder_node ( unsigned int n ) const {
      unsigned int i = 0;
      for ( i = 0; i < tree.size() && n != 0; i++ ) {
        n -= tree[i];
      }

      return i - 1;
    }
Exemplo n.º 5
0
bool isPrimeUtil(ll N,bitset<100007>&_bitset,vector<int>&primes){
    if(N < (int)_bitset.size())
        return _bitset.test(N);
    for(ll i=0; i<primes.size();i++)
        if(N%primes[i]==0)
            return false;
    return true;
}
Exemplo n.º 6
0
void print(bitset<16> &b)
{
    int i = 0;
    int bsize = b.size();
    for (i = 0; i < bsize; ++i)
    {
        cout << b[i];
    }
    cout << " :" << "the size of bitset:" << bsize << endl;
}
Exemplo n.º 7
0
    // restituisco la fine del primo sottoalbero che parte da pos
    inline unsigned int first_subtree ( unsigned int pos ) const {

      unsigned int z;
      unsigned int o;
      for ( z = o = 0, pos++; pos < tree.size(); pos++ ) {
        z += !tree[pos];
        o +=  tree[pos];
        if ( z > o ) break;
      }

      return pos;
    }
Exemplo n.º 8
0
bool cart::should_terminate(const vector<const sample*>& samples,
                           const bitset& splitted_features,
                           size_t min_num_samples)
{
     if (splitted_features.num_bits_set() == splitted_features.size())
     {
         return true;
     }
     if (samples.size() < min_num_samples)
     {
         return true;
     }
     return false;
}
Exemplo n.º 9
0
    void logger::setmask(bitset<8>_mask)
    {
        mask = _mask;
        int bits = 0;
        for (size_t i = 0; i < _mask.size(); i++) {
            if (_mask.test(i)) {
                bits |= logmasks[i];
            }
        }
        // cout << "setlogmask(" << hex << bits << dec << ")" << endl;
#ifdef _WIN32
        WinLog::SetMask(bits);
#else
        setlogmask(bits);
#endif
    }
Exemplo n.º 10
0
/* Decodes Huffman code to original string.
 * 
 * @param code Huffman code.
 * @param root Root of Huffman tree.
 * @return Original string.
 */
string decode_huffman(const bitset& code, HuffmanTree* root)
{
    string origin;
    
    HuffmanTree* curr_node = root;
        
    for (uint i = 0; i <= code.size(); i++) {            
        if (curr_node->symbol != 0) {
            origin += curr_node->symbol;
            curr_node = root;
            i--;
        } else {
            if (code[i] == 0) {
                curr_node = curr_node->left;
            } else {
                curr_node = curr_node->right;
            }
        }
    }
    
    return origin;
}
Exemplo n.º 11
0
void cart::find_best_split(vector<const sample*>& samples,
                          const bitset& splitted_features,
                          tree_node_split& best_split)
{
     /*for each feature f not set in splitted_features
          for each splittable value s of feature f
              R1 = {samples whose feature f's value is smaller than s}
              R2 = {samples whose feature f's value is not smaller than s}
              calculate the cost
                  C = sum{(y1 - c1)^2} + sum{(y2 - c2)^2}
              c1 = mean(y) in R1, c2 = mean(y) in R2
       find (f,s) with mininum C
     */
     //for each feature f
     //  sort samples by f's value
     //  scan samples in ascending order of f's value
     //  for splittable value s
     //  C = sum(y1 ^ 2) + sum(c1 ^ 2) - 2 * c1 * sum(y1) + sum(y2 ^ 2) + sum(c2 ^ 2) - 2 * c2 * sum(y2)
     //  C = CL + CR
     //  c1 = sum(y1) / |CL|
     //  c2 = sum(y2) / |CR|
     //  CL = CLY2 + CLC2 - 2 * c1 * CLY
     //  CR = CRY2 + CRC2 - 2 * c2 * CRY
    double min_ds = -1;
    best_split.fid = splitted_features.size();
    best_split.val = FLT_MIN;
    for (size_t fid = 0; fid < splitted_features.size(); fid++)
    {
        if (splitted_features.test(fid))
        {
            continue;
        }
        //sort samples by feature fid
        feature_comp fcmp(fid);
        std::sort(samples.begin(), samples.end(), fcmp);
        double square_cy1, square_cy2, sum_y1, sum_y2, my1, my2, ds1, ds2;
        size_t ny1, ny2;
        square_cy1 = square_cy2 = sum_y1 = sum_y2 = ny1 = ny2 = my1 = my2 = ds1 = ds2 = 0;
        for (vector<const sample*>::iterator it = samples.begin(); it != samples.end(); it++)
        {
           const sample* sa = *it;
           square_cy2 += sa->y * sa->y;
           sum_y2 += sa->y;
           ny2++;
        }
        for (vector<const sample*>::iterator it = samples.begin(); it != samples.end(); it++)
        {
           const sample* sa = *it;
           //each sample's value is a split value
           square_cy1 += sa->y * sa->y;
           ny1++;
           sum_y1 += sa->y;
           my1 = sum_y1 / ny1;
           ds1 = square_cy1 + my1 * my1 * ny1 - 2 * my1 * sum_y1;
           square_cy2 -= sa->y * sa->y;
           ny2--;
           sum_y2 -= sa->y;
           my2 = sum_y2 / ny2;
           ds2 = square_cy2 + my2 * my2 * ny2 - 2 * my2 * sum_y2;
           if (min_ds < 0 || min_ds > ds1 + ds2)
           {
               min_ds = ds1 + ds2;
               best_split.fid = fid;
               best_split.val = sa->x[fid];
           }
        }
    }
}