示例#1
0
inline void Work(void) { 
    T.clear(); T.Add(b[1], 1); 
    int j = 0; last = 1; 
    for (int i = 2; i <= m; i++) { 
        while (j && Ask(b, i - j, b[i]) != rank[j + 1])  
            j = p[j]; 
        if (j == 0) Ask(b, i - j, b[i]);
        if (Ask(b, i - j, b[i]) == rank[j + 1]) j++; 
        p[i] = j; 
        T.Add(b[i], 1); 
    }
    T.clear(); 
    j = 0; last = 1; 
    for (int i = 1; i <= n; i++) { 
        while (j && Ask(a, i - j, a[i]) != rank[j + 1])
            j = p[j]; 
        if (j == 0) Ask(a, i - j, a[i]);
        if (Ask(a, i - j, a[i]) == rank[j + 1]) j++; 
        if (j == m) { 
            Ans[i] = true;
            j = p[j]; 
        } 
        T.Add(a[i], 1); 
    }
    f[0] = 0;
    for (int i = 1; i <= n; i++) {
//        printf("%d ", Ans[i]);
        f[i] = f[i - 1];
        if (Ans[i] > 0) f[i] = max(f[i], f[i - m] + 1);
    }
//    puts("");
    printf("%d\n", f[n]);
} 
示例#2
0
inline void Prepare(void) { 
    T.clear(); T.n = MAXH; 
    for (int i = 1; i <= m; i++) { 
        rank[i] = make_pair(T.Cal(b[i] - 1) + 1, T.Cal(b[i]));
        T.Add(b[i], 1); 
    }
}
示例#3
0
inline pair<int, int> Ask(int a[], int L, int t) { 
    while (last < L) 
        T.Add(a[last++], -1); 
    return make_pair(T.Cal(t - 1) + 1, T.Cal(t));
}