示例#1
0
inline void Work(void) { 
    T.clear(); T.Add(b[1], 1); 
    int j = 0; last = 1; 
    for (int i = 2; i <= m; i++) { 
        while (j && Ask(b, i - j, b[i]) != rank[j + 1])  
            j = p[j]; 
        if (j == 0) Ask(b, i - j, b[i]);
        if (Ask(b, i - j, b[i]) == rank[j + 1]) j++; 
        p[i] = j; 
        T.Add(b[i], 1); 
    }
    T.clear(); 
    j = 0; last = 1; 
    for (int i = 1; i <= n; i++) { 
        while (j && Ask(a, i - j, a[i]) != rank[j + 1])
            j = p[j]; 
        if (j == 0) Ask(a, i - j, a[i]);
        if (Ask(a, i - j, a[i]) == rank[j + 1]) j++; 
        if (j == m) { 
            Ans[i] = true;
            j = p[j]; 
        } 
        T.Add(a[i], 1); 
    }
    f[0] = 0;
    for (int i = 1; i <= n; i++) {
//        printf("%d ", Ans[i]);
        f[i] = f[i - 1];
        if (Ans[i] > 0) f[i] = max(f[i], f[i - m] + 1);
    }
//    puts("");
    printf("%d\n", f[n]);
} 
示例#2
0
int main(void){
    int T;
    scanf("%d", &T);
    while(T--) {
        scanf("%d", &n);
        int maxa = 0;
        for(int i = 1; i <= n; i++) {
            scanf("%d", a+i);
            maxa = maxa > a[i] ? maxa: a[i];
        }

        BIT t;
        t.resize(maxa);
        t.clear();
        for(int i = 1; i <= n; i++) {
            t.add(a[i], 1);
            c[i] = t.sum(a[i] - 1);
        }
        t.clear();
        for(int i = n; i > 0; i--) {
            t.add(a[i], 1);
            d[i] = t.sum(a[i] - 1);
        }

        long long ans = 0;
        for(int i = 1; i <= n; i++) {
            ans += (long long)c[i]*(n-i-d[i]) + (long long)(i-c[i]-1)*d[i];
        }
        printf("%lld\n", ans);
    }
    return 0;
}
示例#3
0
inline void Prepare(void) { 
    T.clear(); T.n = MAXH; 
    for (int i = 1; i <= m; i++) { 
        rank[i] = make_pair(T.Cal(b[i] - 1) + 1, T.Cal(b[i]));
        T.Add(b[i], 1); 
    }
}