C++ (Cpp) Package::declare_if_needed示例

void Package::compute_type(WrapperStr name, UmlTypeSpec & typespec,
                           Class ** need_object)
{
    typespec.type = 0;
    typespec.explicit_type = 0;

    // no base type like int
    Class * cl;

    if (((cl = Defined[name]) != 0) ||
        ((cl = Undefined[name]) != 0) ||
        ((cl = classes[name]) != 0)) {
        if (need_object != 0)
            *need_object = cl;

        typespec.type = cl->get_uml();

        return;
    }

    UmlClass * uml_cl;

    if ((uml_cl = user_classes[name]) != 0) {
        typespec.type = uml_cl;
        return;
    }

    if ((cl = php_classes[name]) != 0) {
        // a php class
        if (need_object != 0)
            *need_object = cl;

        typespec.type = cl->get_uml();

        return;
    }

    if (need_object == 0)
        typespec.explicit_type = name;
    else if (! Lex::identifierp(name))
        // strange
        typespec.explicit_type = name;
    else {
        // the class does not already exist, create it
        Package * pack = package_unknown();

        cl = pack->declare_if_needed(name, FALSE);
        typespec.type = cl->get_uml();

        *need_object = cl;
    }
}