示例#1
0
static inline bool
nteHasFibEntry(const name_tree::Entry& nte)
{
  return nte.getFibEntry() != nullptr;
}
示例#2
0
static inline bool
predicate_NameTreeEntry_hasFibEntry(const name_tree::Entry& entry)
{
  return static_cast<bool>(entry.getFibEntry());
}